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PROGRAMAR EN VBA MACROS DE EXCEL

How to fill multi-column listbox


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With this VBA macro for Excel, VBA procedure or Excel VBA macro, as it is usually called, is shown fill a listbox that has several columns, with the complication that the data is not in a continuous range but rather arise from a Search data, which depends on the value that is entered in the combobox, ie a value is selected in the combo box, based on that data is obtained, once they were found they are loaded into the listbox, it has Several columns in the case of example 5; Click at the end of the post to download the example.

The example presented here has a close relationship with the macro VBA for Excel, published in my other post that deals with filling a listbox depending on another listbox and combobox.

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The code below must be entered in a form that in the case of the example is named userform1, downloading the example you can see it working, analyze, modify and adapt to what you are doing the code is open without any restriction.

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Code that is inserted into a module
Private Sub Combobox1_Change()
Application.ScreenUpdating = False
Dim fila, a As Integer
On Error Resume Next
‘Borra datos del listbox
ListBox1.Clear
a = 0
fila = 2
While Sheets(«hoja1»).Cells(fila, 5) <> Empty
      dato = Combobox1
  Var = Sheets(«hoja1»).Cells(fila, 5)
   If Sheets(«hoja1»).Cells(fila, 5) = dato Then
         a = ListBox1.ListCount
        ListBox1.AddItem
        ListBox1.List(a, 0) = Sheets(«hoja1»).Cells(fila, 1)
        ListBox1.List(a, 1) = Sheets(«hoja1»).Cells(fila, 2)
        ListBox1.List(a, 2) = Sheets(«hoja1»).Cells(fila, 3)
        ListBox1.List(a, 3) = Sheets(«hoja1»).Cells(fila, 4)
        ListBox1.List(a, 4) = Sheets(«hoja1»).Cells(fila, 5)
   End If
  
fila = fila + 1
Wend
Application.ScreenUpdating = True
End Sub
Private Sub UserForm_Initialize()
Label2.Caption = Sheets(«hoja1»).Cells(1, 1)
Label3.Caption = Sheets(«hoja1»).Cells(1, 2)
Label4.Caption = Sheets(«hoja1»).Cells(1, 3)
Label5.Caption = Sheets(«hoja1»).Cells(1, 4)
Label6.Caption = Sheets(«hoja1»).Cells(1, 5)

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